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Thread: ORTS Standard Engine Files

  1. #71
    Join Date
    Feb 2013
    known universe


    Whoops, left out part of the math for a statement I made below:
    Gross hp minus Traction hp represents a power loss. ( subtract that loss from 100% and you have the locomotives efficiency in converting gross power ( power at the shaft ) to traction power.
    Should read:
    Gross hp minus Traction hp represents a power loss. Divide that power loss by the Gross HP and you get a percentage of loss, substract that from 100% and you arrive at the Locomotive Efficiency.

    4545 (Grosshp) - 4000 ( Tractionhp) = 545hp.
    545/4545 = 0.1199119911991199 ( rounded off to 0.12 or 12% )
    100% - 12% = 88% locomotive efficiency.
    Cheers, R. Steele [Gerry] It's my railroad and I'll do what I want! Historically accurate attitude of US Railroad Barons.

  2. #72
    Join Date
    Feb 2010
    Günzburg, Bayern, Germany


    Wonderful news! I am looking forward to this new release.

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